1929 - Concatenation of Array

1929. Concatenation of Array

Problem Statement

Given an integer array nums of length n, you want to create an array ans of length 2n where ans[i] == nums[i] and ans[i + n] == nums[i] for 0 <= i < n (0-indexed).

Specifically, ans is the concatenation of two nums arrays.

Return the array ans.

 

Example 1:

Input: nums = [1,2,1]
Output: [1,2,1,1,2,1]
Explanation: The array ans is formed as follows:
- ans = [nums[0],nums[1],nums[2],nums[0],nums[1],nums[2]]
- ans = [1,2,1,1,2,1]```

<p><strong class="example">Example 2:</strong></p>

Input: nums = [1,3,2,1] Output: [1,3,2,1,1,3,2,1] Explanation: The array ans is formed as follows:

• ans = [nums[0],nums[1],nums[2],nums[3],nums[0],nums[1],nums[2],nums[3]]
• ans = [1,3,2,1,1,3,2,1]

<p> </p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>n == nums.length</code></li>
<li><code>1 &lt;= n &lt;= 1000</code></li>
<li><code>1 &lt;= nums[i] &lt;= 1000</code></li>
</ul>


<details>
<summary>

#### _Click to open Hints_

</summary>

- Build an array of size 2 * n and assign num[i] to ans[i] and ans[i + n]

</details>

## Solutions

### [_Rust_](concatenation_of_array.rs)

```rs [Rust]
impl Solution {
    pub fn get_concatenation(nums: Vec<i32>) -> Vec<i32> {
        let mut result = nums.clone();

        result.extend(nums);

        result
    }
}

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