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Merge pull request #93 from nhimanshujain/main
Added solution to Leetcode Question - 7 | Reverse Integer
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# Reverse Integer | ||
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Given a signed 32-bit integer ```x```, return ```x``` with its digits reversed. If reversing ```x``` causes the value to go outside the signed 32-bit integer range ```[-231, 231 - 1]```, then return ```0```. | ||
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**Assume the environment does not allow you to store 64-bit integers (signed or unsigned).** | ||
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## Examples | ||
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* Example 1 | ||
``` | ||
Input: x = 123 | ||
Output: 321 | ||
``` | ||
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* Example 2 | ||
``` | ||
Input: x = -123 | ||
Output: -321 | ||
``` | ||
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* Example 3 | ||
``` | ||
Input: x = 120 | ||
Output: 21 | ||
``` | ||
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* Example 4 | ||
``` | ||
Input: x = 0 | ||
Output: 0 | ||
``` | ||
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## Constraints | ||
* -231 <= x <= 231 - 1 |
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class Solution: | ||
def reverse(self, x): | ||
s = str(x) | ||
res = (int('-' + s[1:][::-1]) if s[0] == '-' else int(s[::-1])) | ||
return (res if -2147483648 <= res <= 2147483647 else 0) |