Printing pattern solution

HackerRank Problems/C programs/PointersInC.c

@@ -0,0 +1,20 @@
+#include <stdio.h>
+
+void update(int *a,int *b) {
+    int x, y;
+    x = *a + *b;
+    y = *a - *b;
+    *a = x;
+    *b = abs(y);
+}
+
+int main() {
+    int a, b;
+    int *pa = &a, *pb = &b;
+
+    scanf("%d %d", &a, &b);
+    update(pa, pb);
+    printf("%d\n%d", a, b);
+
+    return 0;
+}

HackerRank Problems/C programs/PrintingPatternUsingLoops.c

@@ -0,0 +1,25 @@
+#include <stdio.h>
+#include <string.h>
+#include <math.h>
+#include <stdlib.h>
+
+int main() 
+{
+
+    int n;
+    scanf("%d", &n);
+  	// Complete the code to print the pattern.
+
+    int len = n*2 - 1;
+    for(int i=0;i<len;i++){
+        for(int j=0;j<len;j++){
+            int min = i < j ? i : j;
+            min = min < len-i ? min : len-i-1;
+            min = min < len-j-1 ? min : len-j-1;
+            printf("%d ", n-min);
+        }
+        printf("\n");
+    }
+    return 0;
+}
+