playlist.py: adding .copy() to locals() preventing kwargs to be sent … #40
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Both static() and basic() functions use kwargs = locals() in order to retrieve the long list of keyword arguments as a dictionary. This is practical, however in python 2.7.6, the actual "kwargs" variable does get scanned by locals() and added as a reference to that dictionary. This ends in kwargs == {...variables key-value pairs..., "kwargs": {the same key-value pairs as before}} and that ugly variable is then sent online to the Echo Nest API.. Using kwargs = locals().copy() removes that kwargs=>kwargs embedded key-value pair.
This also occurs in song.py... Let us check that later.
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This seems to happen maybe only during a debugging session... Or actually does not happen on my production server. I am not sure whether this pull request is really relevant... |
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…over HTTP
Both static() and basic() functions use kwargs = locals() in order to retrieve the long list of keyword arguments as a dictionary. This is practical, however in python 2.7.6, the actual "kwargs" variable does get scanned by locals() and added as a reference to that dictionary. This ends in kwargs == {...variables key-value pairs..., "kwargs": {the same key-value pairs as before}} and that ugly variable is then sent online to the Echo Nest API.. Using kwargs = locals().copy() removes that kwargs=>kwargs embedded key-value pair.
This also occurs in song.py... Let us check that later.