It's with a certain hesitance I post a project based on "Operator Overloading" (generally considered by the programing cognisente as "Unsafe at any speed") but the absence of direct support for regular expressions in Swift provides an excuse to explore the terrain (there are also interesting things you can do with threading operators added further down.) While "NSRegularExpression" is powerful and complete, by the time you fire up an instance up and puzzle out the api the focus has been taken so far away from the expression itself it is seldom the concise solution to a particular class of problem that it should be.
The two new operators defined start with a very basic premise. In the same way that subscripting into a collection such as an array specifies the address or range on which an operation can be performed, subscripting into a string with a regular expression can specify a part of the string that can be assigned to or from. Let's suppose for a moment it would be a good idea to be able to write the following in code:
let input = "Now is the time for all good men to come to the aid of the party"
let words:[String] = input["(\\w+)"].matches()
input["men"] = "people"
// "Now is the time for all good people to come to the aid of the party"
The first expression extracting all words in the text is easy enough to realise. A new operator taking a string subscript on a string returns a SwiftRegex instance which captures the string being operated on and the compiled regular expression specified in the subscript.
extension String {
subscript(pattern: String) -> SwiftRegex {
return SwiftRegex(target: self, pattern: pattern)
}
}
Assignment to this new regular expression entity is a little more problematic. Swift doesn't' give you control the assignment operator itself so I've had to repurpose the "~=" compound operator (it is the "pattern matching" operator after all) so the first iteration is:
var output = input["men"] ~= "people"
The input string is captured by reference so were it to be mutable the operation could be performed in place. A global function RegexMutable() is defined as shorthand to convert an input string into an NSMutableString under the covers so the above code can become:
func RegexMutable(string: NSString) -> NSMutableString {
return NSMutableString(string:string)
}
var mutable = RegexMutable( input )
mutable["men"] ~= "folk"
mutable["the party"] ~= "their country"
// "Now is the time for all good folk to come to the aid of their country"
You can use either version
The SwiftRegex class defines a number of methods to get at all aspects of a match or matches in the input string:
matches() -> [String] // all matches in the string
ranges() -> [NSRange] // array of ranges of matches in string
groups() -> [String] // capture groups of first match
allGroups() -> [[String]] // all groups of all matches
The replacement string is a "template" an can contain "$N" expressions to refer to capture groups in the source regular expression:
mutable["(good) (\\w+)"] ~= "great $2"
A subscript operator as been defined on SwiftRegex itself so capture groups can be extracted and assigned to (this time with a normal "=" assignment.)
let adjective = mutable["(\\w+) (men|people|folk)"][1]
mutable["(good) (\\w+)"][1] = "great"
// "Now is the time for all great folk to come to the aid of their country"
The replacement can also be two forms of closure executed once for each match:
mutable["\\w+"] ~= {
(match: String) in
return match.uppercaseString
}
// "NOW IS THE TIME FOR ALL GREAT FOLK TO COME TO THE AID OF THEIR COUNTRY"
mutable["(\\w)(\\w+)"] ~= {
(groups: [String]) in
return groups[1]+groups[2].lowercaseString
}
// "Now Is The Time For All Great Folk To Come To The Aid Of Their Country"
One final conversion is available, that to a dictionary:
let props = "name1=value1\nname2='value2\nvalue3\n'\n"
let dict = props["(\\w+)=('[^']*'|[^\n]*)"].dictionary()
// ["name1": "value1", "name2": "'value2\nvalue3\n'"]
At which point this almost begins to look useful..
Stop press:
You can now regex a file directly e.g.
RegexFile( "/path/to/file" )["pattern"] ~= "replacement"
And apply replacements inline with chaining
var result = string["pattern"]["replacement"]["pattern2"]["replacement2"]
This is the best syntax I could up with alas..
Copyright (c) 2015 John Holdsworth
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