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Support Pair default fee in RouterV2 #122
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LGTM
let fee = match contract_ref.call().get_fee().try_invoke() { | ||
Ok(Ok(fee)) => fee, | ||
// is not a Pair contract. | ||
let token_0 = match contract_ref.call().get_token_0().try_invoke() { |
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Why suddenly like this & why obtain token0 and token1 differently?
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Because the Pair
contract may not implement get_fee()
, however, it must implement get_token_0()
and get_token_1()
.
Given that get_token_0()
call is successful, we assume that the contract is a Pair
, and there's no need to control the invocation of the get_token_1()
.
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Thank you sir
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