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BlitherBoom812 committed Apr 8, 2024
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22 changes: 21 additions & 1 deletion source/_posts/Antenna.md
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Expand Up @@ -143,7 +143,7 @@ Instantaneous Poynting vector $\vec S(x, y, z, t)$

Radiation Power Density = Time average Poynting vector $\vec S_{av}(x, y, z)=\frac1T\int_0^T\vec S(x, y, z, t)\mathrm dt = \frac12\text{Re}[\tilde{\vec E} \times \tilde{\vec H^*}]$

Total Radiation Power $P_{rad} = \oiint_S[\tilde{\vec E} \times \tilde{\vec H^*}] \cdot \mathrm dv\vec s$
Total Radiation Power $P_{rad} = \oiint_S[\tilde{\vec E} \times \tilde{\vec H^*}] \cdot \mathrm d\vec s$

#### Radiation Intensity

Expand Down Expand Up @@ -240,3 +240,23 @@ $$
![1711695738159](../images/Antenna/1711695738159.png)

二端口网络通常用于描述二天线问题。$S_{11}$表示天线1的反射,$S_{21}$表示天线1到天线2的耦合,均不利于信号的传播。我们希望让$1 - S_{11}^2 - S_{21}^2$尽可能大。

### Link Calculation

#### Friis's Equation

![1712471419276](../images/Antenna/1712471419276.png)

![1712471436962](../images/Antenna/1712471436962.png)

#### ERIP

![1712471499226](../images/Antenna/1712471499226.png)



赫兹偶极子的辐射电阻: $80\pi^2(\frac{\Delta z}{\lambda})^2$,方向性 $\frac{2}{3}$。

#### Radar Equation

![1712473473687](../images/Antenna/1712473473687.png)
66 changes: 66 additions & 0 deletions source/_posts/StaSP.md
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Expand Up @@ -423,3 +423,69 @@ $$
#### LSE

![1711340293644](../images/StaSP/1711340293644.png)

## 贝叶斯估计

贝叶斯MSE:
Bmse$\left(\hat{\theta}\right)=E\left(\left(\theta-\hat{\theta}\right)^2\right)$


$=\int\int\left(\theta-\hat{\theta}\right)^{2}p\big(\mathbf{x},\theta\big)d\mathbf{x}d\theta$ $=\iint\left(\theta-\hat{\theta}\right)^2p\big(\boldsymbol{x}|\theta\big)p\big(\theta\big)d\boldsymbol{x}d\theta$
$=\iint\left(\theta-\hat{\theta}\right)^2p(x|\theta)dxp(\theta)d\theta$

$\hat{\theta}=E\big(\theta|x\big)$

多余参数:未知,但不感兴趣的参数
解决思路:通过积分消除多余参数的影响
(1) 后验概率中存多余参数时:

$$
p(\boldsymbol{\theta},\boldsymbol{\alpha}\mid\boldsymbol{x}) \Rightarrow p (\boldsymbol{\theta}\mid\boldsymbol{x})=\int p(\boldsymbol{\theta},\boldsymbol{\alpha}\mid\boldsymbol{x})\:d\boldsymbol{\alpha}
$$

(2) 条件概率中存在多余参数时:

$$
p(\boldsymbol{\theta}\mid\boldsymbol{x})=\frac{p(\boldsymbol{x}\mid\boldsymbol{\theta})p(\boldsymbol{\theta})}{\int p(\boldsymbol{x}\mid\boldsymbol{\theta})p(\boldsymbol{\theta})d\boldsymbol{\theta}}
$$

$$
\text{若现只有 }p(x|\theta,\alpha)\text{,而无 }p(x|\theta)
$$
此时可通过积分方式解决

$$
p(x\mid\theta)=\int p(x\mid\theta,\alpha)p(\alpha\mid\theta)d\alpha
$$

进一步地,若待估计参数与多余参数相互独立,

$$
p(x\mid\theta)=\int p(x\mid\theta,\alpha)p(\alpha)d\alpha
$$

矢量参数下贝叶斯估计
若 θ 是 $p{\times}1$ 的矢量参数,那么为了估计其中某个参数 $\theta_i$, 可以将剩余参数当作多余参数,因此对$\theta_i$ 的MMSE为

$$
\hat{\theta}_i=E\left(\theta_i\mid x\right)=\int\theta_ip(\theta_i\mid x)d\theta_i
$$
其中

$$
p(\theta_i\mid x)=\int\cdots\int p(\theta\mid x)d\theta_1\cdots d\theta_{i-1}d\theta_{i+1}\cdots d\theta_p
$$

$$
\hat{\theta}_i=\int\theta_i\left(\int\cdots\int p(\boldsymbol{\theta}\mid\boldsymbol{x})\underline{d\theta_1\cdots d\theta_{i-1}d\theta_{i+1}\cdots d\theta_p}\right)d\theta_i=\int\theta_ip(\boldsymbol{\theta}\mid\boldsymbol{x})d\boldsymbol{\theta}
$$

$$
\Longrightarrow\hat{\theta}=\begin{bmatrix}\theta_1p(\theta|x)d\theta\\\int\theta_2p(\theta|x)d\theta\\\vdots\\\int\theta_pp(\theta|x)d\theta\end{bmatrix}=\int\theta_P(\theta|x)d\theta=E(\theta|x)
$$

### 贝叶斯风险

$$
\Re=\iint C(\varepsilon)p(x,\theta)dxd\theta
$$
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