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Make this compiling under -ansi -pedantic flags #7

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Make this compiling under -ansi -pedantic flags #7

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14 changes: 7 additions & 7 deletions md5.c
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Original file line number Diff line number Diff line change
Expand Up @@ -36,9 +36,9 @@ void md5_transform(MD5_CTX *ctx, const BYTE data[])
{
WORD a, b, c, d, m[16], i, j;

// MD5 specifies big endian byte order, but this implementation assumes a little
// endian byte order CPU. Reverse all the bytes upon input, and re-reverse them
// on output (in md5_final()).
/* MD5 specifies big endian byte order, but this implementation assumes a little
* endian byte order CPU. Reverse all the bytes upon input, and re-reverse them
* on output (in md5_final()). */
for (i = 0, j = 0; i < 16; ++i, j += 4)
m[i] = (data[j]) + (data[j + 1] << 8) + (data[j + 2] << 16) + (data[j + 3] << 24);

Expand Down Expand Up @@ -152,7 +152,7 @@ void md5_final(MD5_CTX *ctx, BYTE hash[])

i = ctx->datalen;

// Pad whatever data is left in the buffer.
/* Pad whatever data is left in the buffer. */
if (ctx->datalen < 56) {
ctx->data[i++] = 0x80;
while (i < 56)
Expand All @@ -166,7 +166,7 @@ void md5_final(MD5_CTX *ctx, BYTE hash[])
memset(ctx->data, 0, 56);
}

// Append to the padding the total message's length in bits and transform.
/* Append to the padding the total message's length in bits and transform. */
ctx->bitlen += ctx->datalen * 8;
ctx->data[56] = ctx->bitlen;
ctx->data[57] = ctx->bitlen >> 8;
Expand All @@ -178,8 +178,8 @@ void md5_final(MD5_CTX *ctx, BYTE hash[])
ctx->data[63] = ctx->bitlen >> 56;
md5_transform(ctx, ctx->data);

// Since this implementation uses little endian byte ordering and MD uses big endian,
// reverse all the bytes when copying the final state to the output hash.
/* Since this implementation uses little endian byte ordering and MD uses big endian,
* reverse all the bytes when copying the final state to the output hash. */
for (i = 0; i < 4; ++i) {
hash[i] = (ctx->state[0] >> (i * 8)) & 0x000000ff;
hash[i + 4] = (ctx->state[1] >> (i * 8)) & 0x000000ff;
Expand Down