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SparseMatrixMultiplication.java
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package array;
/**
* Created by gouthamvidyapradhan on 03/12/2017.
*
* Given two sparse matrices A and B, return the result of AB.
You may assume that A's column number is equal to B's row number.
Example:
A = [
[ 1, 0, 0],
[-1, 0, 3]
]
B = [
[ 7, 0, 0 ],
[ 0, 0, 0 ],
[ 0, 0, 1 ]
]
| 1 0 0 | | 7 0 0 | | 7 0 0 |
AB = | -1 0 3 | x | 0 0 0 | = | -7 0 3 |
| 0 0 1 |
Solution: Skip the rows and columns which you already know would result in zero after multiplication.
*/
public class SparseMatrixMultiplication {
/**
* Main method
* @param args
* @throws Exception
*/
public static void main(String[] args) throws Exception{
int[][] A = {{1,0,0,1}};
int[][] B = {{7,0,0}, {0,0,0}, {0,0,1}, {0,0,1}};
int[][] C = new SparseMatrixMultiplication().multiply(A, B);
}
public int[][] multiply(int[][] A, int[][] B) {
boolean[] AH = new boolean[A.length]; // Metadata for matrix A
boolean[] BH = new boolean[B[0].length]; // Metadata for matrix A
for(int i = 0; i < A.length; i ++){
for(int j = 0; j < A[0].length; j ++){
if(A[i][j] != 0){
AH[i] = true;
break;
}
}
}
for(int i = 0; i < B[0].length; i ++){
for(int j = 0; j < B.length; j ++){
if(B[j][i] != 0){
BH[i] = true;
break;
}
}
}
int[][] C = new int[A.length][B[0].length];
for(int i = 0; i < C.length; i ++){
if(AH[i]){
for(int j = 0; j < C[0].length; j++){
if(BH[j]){
int sum = 0;
for(int k = 0; k < A[0].length; k++){
sum += A[i][k] * B[k][j];
}
C[i][j] = sum;
}
}
}
}
return C;
}
}