-
Notifications
You must be signed in to change notification settings - Fork 0
/
day12.cpp
143 lines (109 loc) · 3.76 KB
/
day12.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
/*
--- Day 12: Digital Plumber ---
Walking along the memory banks of the stream, you find a small village that
is experiencing a little confusion: some programs can't communicate with
each other.
Programs in this village communicate using a fixed system of pipes.
Messages are passed between programs using these pipes, but most programs
aren't connected to each other directly. Instead, programs pass messages
between each other until the message reaches the intended recipient.
For some reason, though, some of these messages aren't ever reaching their
intended recipient, and the programs suspect that some pipes are missing.
They would like you to investigate.
You walk through the village and record the ID of each program and the IDs
with which it can communicate directly (your puzzle input). Each program
has one or more programs with which it can communicate, and these pipes
are bidirectional; if 8 says it can communicate with 11, then 11 will say it
can communicate with 8.
You need to figure out how many programs are in the group that contains
program ID 0.
For example, suppose you go door-to-door like a travelling salesman and
record the following list:
0 <-> 2
1 <-> 1
2 <-> 0, 3, 4
3 <-> 2, 4
4 <-> 2, 3, 6
5 <-> 6
6 <-> 4, 5
In this example, the following programs are in the group that contains
program ID 0:
- Program 0 by definition.
- Program 2, directly connected to program 0.
- Program 3 via program 2.
- Program 4 via program 2.
- Program 5 via programs 6, then 4, then 2.
- Program 6 via programs 4, then 2.
Therefore, a total of 6 programs are in this group; all but program 1
which has a pipe that connects it to itself.
How many programs are in the group that contains program ID 0?
--- Part Two ---
There are more programs than just the ones in the group containing program
ID 0. The rest of them have no way of reaching that group, and still might
have no way of reaching each other.
A group is a collection of programs that can all communicate via pipes
either directly or indirectly. The programs you identified just a moment
ago are all part of the same group. Now, they would like you to determine
the total number of groups.
In the example above, there were 2 groups: one consisting of programs
0,2,3,4,5,6, and the other consisting solely of program 1.
How many groups are there in total?
*/
#include <algorithm>
#include <iostream>
#include <set>
#include <sstream>
#include "graph.h"
#include "main.h"
using namespace std;
int mainfunc( istream& is, ostream& os, Part part )
{
Graph<int> g;
set<int> programs;
string line;
while( getline( is, line ) ) {
replace( line.begin(), line.end(), ',', ' ');
istringstream parser( line );
int from;
parser >> from;
string arrow;
parser >> arrow;
while( parser ) {
int to;
parser >> to;
g.addEdge( from, to );
g.addEdge( to, from );
programs.insert( from );
programs.insert( to );
}
}
int count = 0;
for( auto program : programs ) {
if (g.isReachable( 0, program ) ) {
count++;
}
}
set<int> notfound = programs;
int groups=0;
while( notfound.size() ) {
groups++;
int x = *notfound.begin();
notfound.erase( notfound.begin() );
int groupsize = 1;
for( auto iter = notfound.begin(); iter != notfound.end();
/* intr increment below */ ) {
if ( g.isReachable( x, *iter ) ) {
notfound.erase( iter++ );
groupsize++;
} else {
iter++;
}
}
}
if ( part == Part::PART1 ) {
os << count << endl;
} else {
os << groups << endl;
}
return 0;
}