Homework 1 - Leshui He & Leshui Hee & Leshui Heee.ipynb

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    "Q1 (a) the demand function is \n",
    "\\begin{align}\n",
    "Q_d &= 52 - 5*p + 4*p_f +0.1 Y \\\\\n",
    "    &= 52 - 5*p + 8 + 20 \\\\\n",
    "    &= 80 - 5p\n",
    "\\end{align}\n",
    "\n",
    "Inverse the demand function, we get..."
   ]
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   "metadata": {},
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   "source": [
    "from sympy import *"
   ]
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  {
   "cell_type": "code",
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   "source": [
    "p, pf, Y = symbols('p pf Y')"
   ]
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    {
     "data": {
      "text/latex": [
       "$\\displaystyle 0.1 Y - 5 p + 4 pf + 52$"
      ],
      "text/plain": [
       "0.1*Y - 5*p + 4*pf + 52"
      ]
     },
     "execution_count": 6,
     "metadata": {},
     "output_type": "execute_result"
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   ],
   "source": [
    "Qd = 52 - 5*p +4*pf +0.1*Y\n",
    "Qd"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 7,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/latex": [
       "$\\displaystyle 80.0 - 5 p$"
      ],
      "text/plain": [
       "80.0 - 5*p"
      ]
     },
     "execution_count": 7,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "Qd.subs([(pf, 2), (Y, 200)])"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 8,
   "metadata": {},
   "outputs": [],
   "source": [
    "epsilon = symbols('epsilon')"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": []
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