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Because you do this: ids <- stringr::str_extract_all(string = aa, pattern = ";user=[[:alnum:]]+[[:punct:]]")
ids <- stringr::str_extract_all(string = aa, pattern = ";user=[[:alnum:]]+[[:punct:]]")
It will end the regex when it hits any punctuation. That does not work for ids with punctuation, like myself.
Instead do this because ids are 12 characters: ids <- stringr::str_extract_all(string = aa, pattern = ';user=.{12}')
ids <- stringr::str_extract_all(string = aa, pattern = ';user=.{12}')
And then to remove the user part: ids <- ids %>% unlist %>% gsub(";user=", "", .) %>% unique
ids <- ids %>% unlist %>% gsub(";user=", "", .) %>% unique
The text was updated successfully, but these errors were encountered:
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Because you do this:
ids <- stringr::str_extract_all(string = aa, pattern = ";user=[[:alnum:]]+[[:punct:]]")It will end the regex when it hits any punctuation. That does not work for ids with punctuation, like myself.
Instead do this because ids are 12 characters:
ids <- stringr::str_extract_all(string = aa, pattern = ';user=.{12}')And then to remove the user part:
ids <- ids %>% unlist %>% gsub(";user=", "", .) %>% uniqueThe text was updated successfully, but these errors were encountered: