Running Sum of 1d Array

/*
Given an array nums. We define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i]).

Return the running sum of nums.


Input: nums = [1,2,3,4]
Output: [1,3,6,10]
Explanation: Running sum is obtained as follows: [1, 1+2, 1+2+3, 1+2+3+4].
*/

class Solution {
public:
    vector<int> runningSum(vector<int>& nums) {
        int n =nums.size();
        for(int i = 1 ; i< n ; i++){
            nums[i] +=  nums[i-1];
        }
        return  nums;
    }
};