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原文 by @Dytnn
从原理上来说
因此,可以简单的认为, 处于 p1 的任务数量 p1 数量 = min((sealing_thread 总数 - 处于其他阶段的数量), p1 limit 限制)
那么,如果只关注 p1, 可以简单地得出,要么加大 sealing_thread 数量,要么减少处于其他阶段的数量。
其中减少处于其他阶段的数量就是增加其他阶段的吞吐能力。
从现象上来说
在 sealing_thread 一定的情况下,在运行一段时间后,处于稳定状态的情况下:
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