Floor in a sorted array

//Floor in a sorted array

import java.util.*;
import java.lang.*;
import java.io.*;

class Searching {
    public static void main (String[] args)throws IOException {
        BufferedReader read = new BufferedReader(new InputStreamReader(System.in));
        PrintWriter out=new PrintWriter(System.out);
        int t = Integer.parseInt(read.readLine());
        
        while(t-- > 0) {
           String a[] = read.readLine().trim().split("\\s+");
           int n = Integer.parseInt(a[0]);
           long x = Long.parseLong(a[(int)1]);
           String st[] = read.readLine().trim().split("\\s+");
           long arr[] = new long[n];

           for(int i = 0; i < n; i++)
              arr[i] = Long.parseLong(st[i]);
           
           out.println(new Solution().findFloor(arr, n, x));
          
        }
        out.close();
    }    
}

class Solution{
    static int findFloor(long arr[], int n, long x) {
        int i;
        
        for(i = 0; i < n; i++) {
            if(arr[i] > x) {
                break;
            }
        }
        
        return i - 1;
    } 
}