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Hi, nice work and thank you for your sharing !
From my perspective, the pixel in equirectangular projection is proportional to the degree_disparity.
For a 2*pi×pi equirectangular projection map, degree_disparity=i/pi where i in pixel coordinates disparity.
Please correct me if I'm wrong.
The text was updated successfully, but these errors were encountered:
Hi, nice work and thank you for your sharing !
From my perspective, the pixel in equirectangular projection is proportional to the degree_disparity.
For a 2*pi×pi equirectangular projection map, degree_disparity=i/pi where i in pixel coordinates disparity.
Please correct me if I'm wrong.
The text was updated successfully, but these errors were encountered: