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_937.java
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package com.fishercoder.solutions;
import java.util.ArrayList;
import java.util.List;
import java.util.TreeMap;
/**
* 937. Reorder Log Files
*
* You have an array of logs. Each log is a space delimited string of words.
*
* For each log, the first word in each log is an alphanumeric identifier. Then, either:
*
* Each word after the identifier will consist only of lowercase letters, or;
* Each word after the identifier will consist only of digits.
* We will call these two varieties of logs letter-logs and digit-logs. It is guaranteed that each log has at least one word after its identifier.
*
* Reorder the logs so that all of the letter-logs come before any digit-log.
* The letter-logs are ordered lexicographically ignoring identifier, with the identifier used in case of ties.
* The digit-logs should be put in their original order.
*
* Return the final order of the logs.
*
* Example 1:
*
* Input: ["a1 9 2 3 1","g1 act car","zo4 4 7","ab1 off key dog","a8 act zoo"]
* Output: ["g1 act car","a8 act zoo","ab1 off key dog","a1 9 2 3 1","zo4 4 7"]
*
* Note:
* 0 <= logs.length <= 100
* 3 <= logs[i].length <= 100
* logs[i] is guaranteed to have an identifier, and a word after the identifier.
*/
public class _937 {
public static class Solution1 {
public String[] reorderLogFiles(String[] logs) {
TreeMap<String, String> letterLogMap = new TreeMap<>();
List<String> digitLogList = new ArrayList<>();
for (String log : logs) {
int firstSpaceIndex = log.indexOf(' ');
String id = log.substring(0, firstSpaceIndex);
if (Character.isAlphabetic(log.charAt(firstSpaceIndex + 1))) {
String key = log.substring(firstSpaceIndex + 1) + id;
letterLogMap.put(key, log);
} else {
digitLogList.add(log);
}
}
String[] reorderedLogs = new String[logs.length];
int i = 0;
for (String key : letterLogMap.keySet()) {
reorderedLogs[i++] = letterLogMap.get(key);
}
for (String log : digitLogList) {
reorderedLogs[i++] = log;
}
return reorderedLogs;
}
}
}