-
Notifications
You must be signed in to change notification settings - Fork 0
/
LeetCode
47 lines (35 loc) · 1.02 KB
/
LeetCode
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
#include<iostream>
#include<string>
using namespace std;
/*
You're given strings J representing the types of stones that are jewels, and S representing the stones you have. Each character in S is a type of stone you have. You want to know how many of the stones you have are also jewels.
The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so "a" is considered a different type of stone from "A".
Example 1:
Input: J = "aA", S = "aAAbbbb"
Output: 3
Example 2:
Input: J = "z", S = "ZZ"
Output: 0
Note:
S and J will consist of letters and have length at most 50.
The characters in J are distinct.
*/
int numJewelsInStones(string J, string S) ;
int main(void)
{
string J = "aA";
string S = "aAAbbbb";
cout<<(numJewelsInStones(J,S))<<endl;
return 0;
}
int numJewelsInStones(string J, string S) {
int count=0;
for(int i=0;S[i]!='\0';i++)
for(int k=0;J[k]!='\0';k++)
if (S[i]==J[k])
{
count++;
break;
}
return count;
}