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code.cpp
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/* **************************************************************************
* Copyright 2024 The OpenGenus.org Authors. All Rights Reserved.
*
* Code for the book "DAILY 43: Algorithmic Problems for Coding Interviews: Easy level, C++ edition"
*
* Licensed under the GNU General Public License, Version 3.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.gnu.org/licenses/gpl-3.0.html
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*
* For details about the book, please visit: https://www.amazon.com/dp/B0CZJNBLQS
* *************************************************************************/
#include <iostream>
class ListNode {
public:
int val;
ListNode *next;
ListNode(int x) : val(x), next(nullptr) {}
};
class Solution {
public:
// Check Palindrome Linked List
// using slow and fast pointers
bool isPalindrome(ListNode* head) {
ListNode *slow = head, *fast = head, *prev, *temp;
// Slow and fast pointers
// Identify middle node with slow pointer
while (fast && fast->next) {
slow = slow->next;
fast = fast->next->next;
}
// Reverse the second half of Linked List
prev = slow;
slow = slow->next;
prev->next = NULL;
while (slow) {
temp = slow->next;
slow->next = prev;
prev = slow;
slow = temp;
}
// Check palindrome by comparing the two halves
// One half: From head to middle
// Second half: From middle to end (reversed half)
fast = head;
slow = prev;
while (slow) {
if (fast->val != slow->val)
return false;
else {
fast = fast->next;
slow = slow->next;
}
}
return true;
}
};
// Utility function to print the linked list
void printList(ListNode* head) {
ListNode* temp = head;
while (temp) {
std::cout << temp->val << " ";
temp = temp->next;
}
std::cout << std::endl;
}
int main() {
// Example usage
ListNode *head = new ListNode(1);
head->next = new ListNode(2);
head->next->next = new ListNode(3);
head->next->next->next = new ListNode(2);
head->next->next->next->next = new ListNode(1);
std::cout << "Original Linked List: ";
printList(head);
Solution solution;
bool palindrome = solution.isPalindrome(head);
if (palindrome)
std::cout << "The linked list is a palindrome." << std::endl;
else
std::cout << "The linked list is not a palindrome." << std::endl;
// Clean up memory
ListNode *temp;
while (head) {
temp = head;
head = head->next;
delete temp;
}
return 0;
}