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Define x // 3 for an interval x #670

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dpsanders opened this issue Jun 4, 2024 · 2 comments
Closed

Define x // 3 for an interval x #670

dpsanders opened this issue Jun 4, 2024 · 2 comments

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@dpsanders
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ff(x) = x // 3

ff(1..2)

gives

ERROR: MethodError: no method matching //(::Interval{Float64}, ::Int64)
@dpsanders
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dpsanders commented Jun 4, 2024 •
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Similarly for

ff(x) = x // interval(3)

@OlivierHnt
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This was done on purpose because // is a constructor for the Rational type.

This is consistent with eg

julia> 1.0//1
ERROR: MethodError: no method matching //(::Float64, ::Int64)

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@dpsanders @OlivierHnt