Pass shared_ptr object to c++ function as pointer

[SergeyStrGroup]

Hi!
Is it possible to take pointer from shred_ptr in julia?

I found the following behaviour:

Here is a binded class:

   types.add_type<DataBase>("DataBase")
      .method("AddMaterial", &DataBase::addMaterial);

    types.method("GetTemplate", [](DataBase *db, const std::string &name) -> PropTemplate 

Lets return raw pointer to DataBase:

    db = OpenDb()
    println(typeof(db)) # CxxPtr{DataBase}
    AddMaterial(db, "", InN)           # ok
    templ = GetTemplate(db[], "")  # ok

its ok.

Let return stdL::shared_ptr

    db = OpenDb()
    println(typeof(db)) # CxxWrap.StdLib.SharedPtrAllocated{DataBase}
    AddMaterial(db[], "", InN)         # ok
    templ = GetTemplate(db[], "")  # error

i got error trying to pass shared_ptr[] to non member function taking pointer.

Its obvious that operator[] return reference and there is internal workaround for members.

Is it possible to get it work same way for member and non member functions? (Could i add some function taking pointer from shared_ptr?)

(i have a lot of function taking pointers, and get 20% slow down on simple functions taking reference)

Thanks!

[barche]

The reason it works differently for a member function is to facilitate applying a member function to both pointers and references (since Julia has no concept of member functions, and in C++ there is no overloading with respect to the owning object). For free functions on the other hand, a C++ library may provide different overloads taking pointers or references, so we can't just automate this.

The two options are:

1. Add an overload for references (or even shared pointers): types.method("GetTemplate", [](DataBase& db, const std::string &name)
2. Get the normal pointer: templ = GetTemplate(CxxPtr(db[]), "")