-
Notifications
You must be signed in to change notification settings - Fork 572
/
scapegoat_tree.go
139 lines (122 loc) · 2.99 KB
/
scapegoat_tree.go
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
package copypasta
/* 替罪羊树
https://en.wikipedia.org/wiki/Scapegoat_tree
https://people.ksp.sk/~kuko/gnarley-trees/Scapegoat.html
lazy insert: let the tree grow and from time to time, when a subtree gets too imbalanced,
rebuild the whole subtree from scratch into a perfectly balanced tree
lazy delete: just mark the node for deletion; when n/2 nodes are marked,
rebuild the whole tree and throw away all deleted nodes
推荐:常见平衡树的α值+复杂度分析 https://riteme.site/blog/2016-4-6/scapegoat.html
https://oi-wiki.org/ds/sgt/
【可视化】https://www.bilibili.com/video/BV1sP4y1i7WB/
https://zhuanlan.zhihu.com/p/21263304
https://zhuanlan.zhihu.com/p/180545164
https://taodaling.github.io/blog/2019/04/19/%E6%9B%BF%E7%BD%AA%E7%BE%8A%E6%A0%91/
模板题 https://www.luogu.com.cn/problem/P3369 https://www.luogu.com.cn/record/136284078
https://www.luogu.com.cn/problem/P6136
https://codeforces.com/contest/455/problem/D
*/
type sgtNode struct {
lr [2]*sgtNode
key int
val int // 如果是可重集,val 也可以当作删除标记
sz int
del bool // 删除标记
}
func (o *sgtNode) cmp(b int) int {
switch {
case b < o.key:
return 0 // 左儿子
case b > o.key:
return 1 // 右儿子
default:
return -1
}
}
func (o *sgtNode) size() int {
if o != nil {
return o.sz
}
return 0
}
func (o *sgtNode) maintain() {
o.sz = o.lr[0].size() + o.lr[1].size()
if !o.del { // o.val > 0
o.sz++
}
}
func (o *sgtNode) nodes() []*sgtNode {
nodes := make([]*sgtNode, 0, o.size())
var f func(*sgtNode)
f = func(o *sgtNode) {
if o == nil {
return
}
f(o.lr[0])
if !o.del { // o.val > 0
nodes = append(nodes, o)
}
f(o.lr[1])
}
f(o)
return nodes
}
func buildSGT(nodes []*sgtNode) *sgtNode {
if len(nodes) == 0 {
return nil
}
m := len(nodes) / 2
o := nodes[m]
o.lr[0] = buildSGT(nodes[:m])
o.lr[1] = buildSGT(nodes[m+1:])
o.maintain()
return o
}
func (o *sgtNode) rebuild() *sgtNode { return buildSGT(o.nodes()) }
type scapegoatTree struct {
root *sgtNode
delCnt int
}
func (t *scapegoatTree) _put(o *sgtNode, key, val int) *sgtNode {
if o == nil {
return &sgtNode{key: key, val: val, sz: 1}
}
if d := o.cmp(key); d >= 0 {
o.lr[d] = t._put(o.lr[d], key, val)
} else {
if o.del { // o.val == 0
o.del = false
t.delCnt--
}
//o.val = val
o.val += val
}
o.maintain()
if sz := o.size() * 3; o.lr[0].size()*4 > sz || o.lr[1].size()*4 > sz { // alpha=3/4
return o.rebuild()
}
return o
}
func (t *scapegoatTree) put(key, val int) { t.root = t._put(t.root, key, val) }
func (t *scapegoatTree) _delete(o *sgtNode, key int) {
if o == nil {
return
}
if d := o.cmp(key); d >= 0 {
t._delete(o.lr[d], key)
} else if !o.del { // o.val > 0
//o.val--
o.del = true
t.delCnt++
}
o.maintain()
}
func (t *scapegoatTree) delete(key int) {
t._delete(t.root, key)
if t.delCnt > t.root.size()/2 {
t.root = t.root.rebuild()
t.delCnt = 0
}
}
// 其余和 BST 有关的方法见 bst.go
// 注意求前驱后继的写法